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Matrix Inverse Method | Class 11 Maths Ex 2.6 Q6 Help

Updated 2 min read

In short

Master the 3x3 Matrix Inverse Method. Step-by-step Urdu/Hindi guide for Class 11 Maths Ex 2.6, Q6. Solve linear equations easily with Hamza's tips.

On this page6 sections

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Detailed Methodology

The Matrix Inverse Method (also known as the Inversion Method) is a powerful algebraic tool used to solve systems of linear equations. While students often learn this for 2x2 matrices in 9th grade, the 11th-grade curriculum (National Book Foundation) expands this to 3x3 systems, requiring a deep understanding of determinants, cofactors, and adjoints.

1. Matrix Formation

First, convert the system of linear equations into a matrix equation AX = B.

  • Matrix A: Contains the coefficients of variables (x, y, z).
  • Matrix X: The column matrix of variables [x, y, z].
  • Matrix B: The constants on the right side of the equations.

2. The Determinant Check

Calculate |A| by expanding along the first row (R1).

Important:

If |A| = 0, the matrix is singular, and the system has no solution. Do not proceed further.

Finding the Adjoint of a 3x3 Matrix

This is the most time-consuming part. Follow the Co-factor Method meticulously:

Calculate Minors

Find the determinant of the 2x2 matrix remaining after hiding the row and column of an element.

Apply Signs

Use the sign pattern:
+ - +
- + -
+ - +

Transpose Matrix

Swap the rows and columns of your co-factor matrix to finally get Adj(A).

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3. Solving for X

Once you have the inverse matrix A-1 = Adj(A) / |A|, multiply it by Matrix B.

Operation Description
Scalar Division Raja Hamza Khan recommends dividing by the determinant (|A|) at the very last step to avoid working with messy fractions too early.
Row × Column Multiply the rows of A-1 by the single column of B.
Verification Always plug your final values (x, y, z) back into the original equations to check for accuracy.

Special Case: Question 6 Part 4

When variables appear in the denominator (e.g., 2/x + 3/y + 10/z = 4), Hamza explains a clever workaround:

Let 1/x = u
Let 1/y = v
Let 1/z = w

Solve for [u, v, w] as usual, then find the reciprocal of your answers to get the final values of [x, y, z].

  • #matrix inverse
  • #matrix method
  • #class 11
  • #qst year

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